Since I am able to lower the thrust line by rotating the Victor 1+ belt reduction unit, I have become curious as to what effect it would have on pitch trim. As I have lowered the thrust line, it seems that the cruise speed noise level has decreased. I put together the above diagram so that I could solve for L or Lift in the general case. Then by substituting in various dimensions and loads (forces) to determine their effect on Lift or wing load and tail load at cruise.
The dynamic analysis goes like this.
Sum of Forces in x -> 0=D-F therefore D=F
Sum of Forces in y -> 0=L-W-T therefore T=L-W
and
Sum of Moments about x/y axes -> 0=(Ta)-(Fb)-(Dc)-(Ld)
Where at cruise:
T is horizontal tail down load force
F is propeller thrust force
L is total lift force
D is total drag force
W is total weight force
and
a, b, c, and d are the perpendicular distances from the x or y axis.
By eliminating T the following lift equation can be obtained:
L=[F(c + b)+Wa]/(a-d)
To make things easier, I placed the x axis through the center of the rear wing tube. From this point it is easy to measure and or estimate the perpendicular distances.
The Weight force passes through the CG. To minimize the moment effect of CG location with the center of Lift, I chose to use the most to the rear CG of 37%. I have no idea where the center of drag would be, but I assumed that it was below the trailing edge of the wing. The same is true of the Lift force. I put it displaced it back from the CG to ensure that the FireFly would be stable. The thrust Force was computed using JAVAPROP while assuming the Victor 1 was putting out 38 hp at 5200 rpm with a 2.7 ratio belt reducer driving a 56 inch diameter propeller pushing the FireFly 63 mph.
The perpendicular distances measured/calculated/estimated:
a = 139"
b - Rotax 447 = 12"
b - Victor 1 @ 0° = 15.33"
b - Victor 1 @ 45° = 13.72"
b - Victor 1 @ 135° = 5.94"
c = 6"
d = 6"
Other assumptions:
W=480#
F=140#
Putting all values in but thrust line height b gives:
L=508+1.053b#
T=28+1.053b#
With belt reducer set at 0 degrees:
L=524#
T=44#
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